In Java, you can create a Thread using Lambda expression by leveraging ‘Runnable’ functional interface. It’s very simple and straight-forward approach to create thread by defining run method of the interface. How to create Thread using Lambda expression in Java?
Simplest way to Create Thread using Lambda Expression in Java 8 Share on X
Here’s an example:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 | /** * Using Java 8, Create a Thread using Lambda Expression * @author Deepak Verma * */ public class Create_Thread_using_Lambda_Expression_in_Java8 { public static void main(String[] args) { // Using lambda expression to create a thread Thread myThread = new Thread(() -> { for (int i = 0; i < 5; i++) { System.out.println("Thread is running: " + i); } }); // Start the thread myThread.start(); } } |
Output:
1 2 3 4 5 | Thread is running: 0 Thread is running: 1 Thread is running: 2 Thread is running: 3 Thread is running: 4 |
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In this example:
- We create a
Threadobject and pass a lambda expression as the argument to theThreadconstructor. The lambda expression represents therun()method of theRunnableinterface. - Inside the lambda expression, we define the code that the thread will execute. In this case, it’s a simple loop printing a message.
The above code demonstrates how to create a thread using lambda expressions in a concise and expressive manner. Note that lambda expressions are particularly useful when you need to provide a simple implementation for functional interfaces like Runnable or Callable.
Simplest way to create Thread using Lambda in Java 8..!!! Share on X
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