In this tutorial, we will see “How to find Duplicate Characters and their count in a String using Java 8?”
Find Duplicate Characters in String in Java 8
Java 8 – How to find Duplicate Characters and their Count in a String? Share on X
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 | /** * Find Duplicate Characters in String using Java 8 Stream * @author Deepak Verma * */ import java.util.LinkedHashMap; import java.util.Map; import java.util.stream.Collectors; public class Find_Duplicate_Characters_In_String_Java8_Example { public static void main(String[] args) { String sampleString = "Techndeck"; checkDuplicateCharacters(sampleString); } public static void checkDuplicateCharacters(String sampleString) { Map<Character, Long> characterCount = sampleString.chars() .mapToObj(c -> (char) c) .collect(Collectors.groupingBy(c -> c, LinkedHashMap::new, Collectors.counting())); characterCount.entrySet().stream() .filter(c -> c.getValue() > 1) .forEach(c -> System.out.printf("Duplicate Character - %s \ncount - %d %n", c.getKey(), c.getValue())); } } |
Output:
1 2 3 4 | Duplicate Character - e count - 2 Duplicate Character - c count - 2 |
check if text or string present in a file using java 8
In above example, we first uses the chars() method to generate a stream of the characters in the original string. Then we uses the mapToObj method to convert the int values of the characters to their corresponding char values. After that, we uses the groupingBy collector to group the characters by their value, creating a map where the keys are the unique characters in the string and the values are the number of occurrences of each character. And at last, we filters the map to only include characters that occur more than once and then using the forEach method, prints out the duplicate characters and their count.
Find Duplicate Characters in String in Java 8
skip method java 8 stream
Java 8 – How to find Duplicate Characters and their Count in a String? Share on X
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