In this tutorial, we will see “How to check if a number is an Armstrong Number using Java?”
Check if number is Armstrong number in java
Java – How to check if number is an Armstrong Number? Click To Tweet
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 | /** * Check Armstrong Number in Java * @author Deepak Verma * */ public class Check_If_Number_is_Armstrong_Number_Java8_Example { public static void main(String[] args) { int number = 250; if (isArmstrongNumber(number)) System.out.println(number + " is an Armstrong number."); else System.out.println(number + " is not an Armstrong number."); } public static boolean isArmstrongNumber(int number) { int originalNumber = number; int result = 0; int n = String.valueOf(number).length(); while (number != 0) { int digit = number % 10; result += Math.pow(digit, n); number /= 10; } return originalNumber == result; } } |
Output:
1 | 250 is not an Armstrong number. |
check if text or string present in a file using java 8
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Java – How to check if number is an Armstrong Number? Click To Tweet
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