In this tutorial, we will see “How to check if a number is an Armstrong Number using Java?”
Check if number is Armstrong number in java
Java – How to check if number is an Armstrong Number? Share on X
/**
* Check Armstrong Number in Java
* @author Deepak Verma
*
*/
public class Check_If_Number_is_Armstrong_Number_Java8_Example {
public static void main(String[] args) {
int number = 250;
if (isArmstrongNumber(number))
System.out.println(number + " is an Armstrong number.");
else
System.out.println(number + " is not an Armstrong number.");
}
public static boolean isArmstrongNumber(int number) {
int originalNumber = number;
int result = 0;
int n = String.valueOf(number).length();
while (number != 0) {
int digit = number % 10;
result += Math.pow(digit, n);
number /= 10;
}
return originalNumber == result;
}
}
Output:
250 is not an Armstrong number.
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Java – How to check if number is an Armstrong Number? Share on X
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